6p^2+16=20p

Solution for 6p^2+16=20p equation:

6p^2+16=20p

We move all terms to the left:

6p^2+16-(20p)=0

a = 6; b = -20; c = +16;
Δ = b2-4ac
Δ = -202-4·6·16
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4}{2*6}=\frac{16}{12}
=1+1/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4}{2*6}=\frac{24}{12}
=2
$